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x^2-2.38596x-0.2418=0
a = 1; b = -2.38596; c = -0.2418;
Δ = b2-4ac
Δ = -2.385962-4·1·(-0.2418)
Δ = 6.6600051216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.38596)-\sqrt{6.6600051216}}{2*1}=\frac{2.38596-\sqrt{6.6600051216}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.38596)+\sqrt{6.6600051216}}{2*1}=\frac{2.38596+\sqrt{6.6600051216}}{2} $
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